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13x^2+29x+13=0
a = 13; b = 29; c = +13;
Δ = b2-4ac
Δ = 292-4·13·13
Δ = 165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{165}}{2*13}=\frac{-29-\sqrt{165}}{26} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{165}}{2*13}=\frac{-29+\sqrt{165}}{26} $
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